Respuesta :

Ethylene Burns in the presence of O₂ to produce CO₂ and H₂O vapors;

                               C₂H₄  +  3 O₂   →   2 CO₂  +  2 H₂O

According to equation, 

22.4 L (1 mole) C₂H₄ reacts completely to produce  =  44.8 L (2 moles) of H₂O

So, 

1.65 L of C₂H₄ on complete reaction will produce  =  X L of H₂O

Solving for X,

                                  X  =  (1.65 L × 44.8 L) ÷ 22.4 L

                                  X  =  3.3 L of H₂O