Respuesta :
Not sure what the question is, but the quotient is -2x+5.
We first look for the number of times x² goes into -2x³. It goes in -2x times. This goes over -23x in the box. Multiply back by the divisor, and the product we write under the dividend in the box is
-2x³+6x²-8x
We now have this subtraction:
-2x³+11x²-23x
-(2x³+ 6x²- 8x)
Which gives us
5x²-15x
Bring down the 20 from the dividend and we have
5x²-15x+20
Now we see how many times x² will go into 5x². It goes 5 times, so we write +5 beside our -2x in the quotient. Multiply 5 by the divisor, and we have the following to write under the next line in our process:
5x²-15x+20
When we subtract this from the previous line, we have 0 remainder.
We first look for the number of times x² goes into -2x³. It goes in -2x times. This goes over -23x in the box. Multiply back by the divisor, and the product we write under the dividend in the box is
-2x³+6x²-8x
We now have this subtraction:
-2x³+11x²-23x
-(2x³+ 6x²- 8x)
Which gives us
5x²-15x
Bring down the 20 from the dividend and we have
5x²-15x+20
Now we see how many times x² will go into 5x². It goes 5 times, so we write +5 beside our -2x in the quotient. Multiply 5 by the divisor, and we have the following to write under the next line in our process:
5x²-15x+20
When we subtract this from the previous line, we have 0 remainder.
Answer:
the answer is D.20
Step-by-step explanation:
i guessed on the test and got it right
