54.2 watts of energy are wasted as heat by this lighting.
It is the rate of the electric work done. Its unit is the watt. Horsepower is also the unit of power.
Given data;
Power of lightbulb,P₀ = 55w
Efficiency,[tex]\rm \eta[/tex] = 1.6%
Power wasted,[tex]\rm P_i[/tex]
The power efficiency is found as;
[tex]\rm \eta = \frac{P_{0}}{P_{i}} \\\\ P_0 = \eta \times P_i \\\\ P_0 =1.6 \times 55 \ w \\\\ P_0 = 54.2 \ w[/tex]
Hence power is wasted as heat by this lightbulb will be 54.2 watts.
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