Respuesta :
OK, so the equation linking current, charge and time is Current = charge/time. So if we substitute the figures for the first question, it is 0.005A = 2.00C/t (remember to convert all to SI units). Rearrange and we get:
t=2.00C/0.005A= 400 seconds
For the second question, we need to first convert the electrons to coulombs. So (1 electron is 1.609*10^-19 C), so 3.75x10^14 electrons is 0.0000603375 C. So now we apply the numbers to formula above.
Time = 0.0000603375 C /60.0A = 0.000001005625 seconds.
t=2.00C/0.005A= 400 seconds
For the second question, we need to first convert the electrons to coulombs. So (1 electron is 1.609*10^-19 C), so 3.75x10^14 electrons is 0.0000603375 C. So now we apply the numbers to formula above.
Time = 0.0000603375 C /60.0A = 0.000001005625 seconds.
The time taken for the given quantity of charge to pass through the wire is 400 seconds.
Given the data in the question;
- Current; [tex]I = 5.00mA = 0.005A[/tex]
- Quantity of charge; [tex]Q = 2.00C[/tex]
- Time; [tex]t = ?[/tex]
Current
Current can be referred to as the electric charge transferred per unit time, it is the rate of flow of electric charge.
It is expressed as;
[tex]I = \frac{Q}{t}[/tex]
Where Q is quantity of charge and t is time elapsed.
To determine the time taken for the charge to pass through the wire, we substitute our given values into the expression above.
[tex]I = \frac{Q}{t} \\\\0.005A = \frac{2.00C}{t}\\ \\t = \frac{2.00C}{0.005A}\\ \\t = 400s[/tex]
Therefore, the time taken for the given quantity of charge to pass through the wire is 400 seconds.
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