The two numbers are 27 and 9.
It is given that, one number is 3 times as large as the other. Let the two numbers are [tex]x[/tex] and [tex]3x[/tex].
The sum of two numbers is 36. So,
[tex]x+3x=36[/tex]
[tex]4x=36[/tex]
[tex]x=\dfrac{36}{4}[/tex]
[tex]x=9[/tex]
The one number is 9 and the other number is:
[tex]3x=3(9)[/tex]
[tex]3x=27[/tex]
Therefore, the required numbers are 27 and 9.
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