Respuesta :

kenmyna
  Mg(No3)2  is  calculated   as  follows

moles  =  mass/molar  mass
the  molar  mass  of  Mg(NO3)2  is =  148 g/mol

moles  is  therefore= 2.25 g /  148  g/mol= 0.0152  moles

Mg(No3)2   contain  0.0152  moles  of  the   compound 
Oseni

2.23 g sample of magnesium nitrate would contain 0.015 moles of the compound

Number of Moles

The number of moles of a compound is the ratio of the mass of the substance and that of its molar mass.

Mathematically, mole = mass/molar mass

Thus, 2.25 g of Mg(NO3)2 will have = 2.25/148.3

                                                           = 0.015 moles

More on number of moles can be found here: https://brainly.com/question/14919968

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