Respuesta :

calculista
the correct question is
ABCD is a rectangle. what is the length of the diagonals if AC= 3y/5 and BD= 3(y-4)

see the figure attached to better understand the problem

we know that
Given AC and BD are diagonals. In a rectangle diagonals are equal.

Therefore AC = BD

=> 3y/5 = 3y - 4

=> 3y = 5(3y - 4)

=> 3y = 15y - 20

=> 12y = 20

=> y = 20/12 = 5/3

Therefore AC = 3y/5

= 3(5/3)/5

= 1 units

and BD = 3y - 4

= 3(5/3) - 4

= 5 - 4

= 1 units

the answer is

The length of each diagonal is 1 units

Ver imagen calculista

Otras preguntas