Krishmamuradi
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A card game is being played and the 8 of spades and 10 of hearts are drawn from a single deck. In order to win, the next card the player draws from the deck must be higher than the highest card already drawn. What is the probability that the next card the player draws is a winning card? (An ace is considered to have a value of 1 and jacks, queens, and kings have a value of 10.) Hint: A deck has 52 cards, 4 suits, and each suit has A, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K. A. 3% B. 8% C. 24% D. 25%

Respuesta :

The way the question is worded, the correct answer is 0%. A 10 has already been drawn, and there are ZERO ways to draw a card valued higher than 10. The question specifically says face cards- J, Q, K- are worth 10, so the best the player can do is tie the 10, but not beat it.

However, among the answers given, it appears C is correct, if you assume that the face cards are higher valued than the 10 of hearts. There are 12 face cards remaining in the deck, 4 each of J, Q, K. And there is a total of 50 cards remaining after drawing the 8 and the 10.

[tex] \frac{12}{50} *100=24 \text{ percent}[/tex]

There’s a 24% chance we’ll draw a winning card IF the assumption is that face cards beat a 10.

The probability/chance of drawing a winning card if the assumption is that face cards beat a 10 is; 24%

How to solve Card Probability Problems?

If we assume that the face cards are higher valued than the 10 of hearts, then it means we can say that there are 12 face cards remaining in the deck.

Now, out of the 12 cards remaining in the deck, we can say that there are 4 each of J, Q, K. Also, there is a total of 50 cards remaining after drawing the 8 and the 10.

Thus, the chance of drawing a winning card if the assumption is that face cards beat a 10 is;

12/50 * 100% = 24%

Read more about Card Probability at; https://brainly.com/question/5858025

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