Explanation :
It is given that,
Potential, [tex]V=4\ mV=4\times 10^{-3}\ V[/tex]
This potential across the person's chest is at a distance of 0.250 m
Frequency of electromagnetic wave, f = 1 Hz
We know that the electric field is defined as :
[tex]E=\dfrac{V}{d}[/tex]
V is the potential
d is the distance
[tex]E=\dfrac{4\times 10^{-3}\ V}{0.250\ m}[/tex]
[tex]V=0.016\ V/m[/tex]
So, the maximum electric strength is 0.016 V/m.
Hence, this is the required solution.
