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For you to find the correct element, begin by looking only at the fourth row of elements on the periodic table, as indicated by the 4 in front of the 4p. This number tells you the level, or shell, in which these electrons will reside.

The “p” block is the column containing six individual columns of elements on the right most side of the table. In this configuration, elements can have from one “p” electron, up to six.

The question is asking for the element containing 4 “p” electrons, so on the fourth row of the “p” block, count out each element until you reach four “4p” electrons.

4p1-Gallium
4p2-Germanium
4p3-Arsenic
4p4-Selenium

Selenium, atomic number 34, is the element in the fourth row containing four “p” electrons.
Histrionicus

The Selenium element in the fourth period of the periodic table with a total of 4 4p electrons.

The fourth  period has 18 elements including s block and p block, it begins with potassium having the electronic configuration as shown.  

  • [tex]1s^22s^22p^63s^23p^64s^1[/tex]

The p block of the fourth period, as it is asked 4p, has the following elements

  • Ga Gallium          ....3d10 4s2 4p1
  • Ge Germanium   ....3d10 4s2 4p2
  • As Arsenic          ......3d10 4s2 4p3
  • Se Selenium .....3d10 4s2 4p4
  • Br Bromine           ...3d10 4s2 4p5
  • Kr Krypton            ..3d10 4s2 4p6  

This period ends with krypton having the electronic configuration as shown.

  • [tex]1s^22s^22p^63s^23p^63d^{10}4s^24p^6[/tex]

Thus, the Selenium element in the fourth period of the periodic table with a total of 4 4p electrons.

Learn more about p- block elements:

https://brainly.com/question/14472338

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