Respuesta :
The number of moles of NaOh that are contained in 65ml of 2.20M solution NaOh in H2o is calculated using the below formula
moles = molarity x volume /1000
that is 65 x2.20 /1000= 0.143 moles
moles = molarity x volume /1000
that is 65 x2.20 /1000= 0.143 moles
Explanation:
Molarity is defined as number of moles divided by volume in liter.
Mathematically, Molarity = [tex]\frac{no. of moles}{Volume in liter}[/tex]
Since, it is known that 1 L equals 1000 ml so 65.0 mL equals 0.065 L.
Therefore, it is given that volume is 0.065 L and molarity is 2.20 M. Hence, calculate number of moles as follows.
Molarity = [tex]\frac{no. of moles}{Volume in liter}[/tex]
Number of moles = [tex]Molarity \times Volume in liter[/tex]
= [tex]2.20 M \times 0.065 L[/tex]
= 0.143 mol
Thus, we can conclude that there are 0.143 moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in [tex]H_2O[/tex].