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If we expect to get a number less than 3 in eighty times spinning an eight-part spinner numbered 1 to 8, how many times would we have spun?

60
120
240
320

Respuesta :

jcherry99
You have eight numbers in total. Only two (1 and 2 are less than 3. You do not include 3) of them will bring success.
Let x = the total number of times you need to spin.

(2/8)x = 80 Multiply by 8
2x = 80 * 8
2x = 640 Divide by 2
x = 640 / 2
x = 320

D <<<< answer. 

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