Can someone help me with algebra?

What is the least common denominator of the fraction 7 over 3 x plus the fraction 2 over x plus the fraction x over x minus 1?

3x − 1
3(x2 − 1)
3(x − 1)
3x(x − 1)

thanks in advanced :))

Respuesta :

the answer is 3x( x - 1 )

Answer:

The least common denominator of the fraction is:

                            3x(x − 1)

Step-by-step explanation:

We are given a algebraic expression in terms of the variable x as follows:

The fraction 7 over 3 x plus the fraction 2 over x plus the fraction x over x minus 1.

Mathematically it is expressed as follows:

        [tex]=\dfrac{7}{3x}+\dfrac{2}{x}+\dfrac{x}{x-1}[/tex]

Hence, on taking the Least common Multiple we get:

    [tex]=\dfrac{7(x-1)+2\times 3(x-1)+x\times 3x}{3x(x-1)}[/tex]

which is given by:

[tex]=\dfrac{7x-7+6x-6+3x^2}{3x(x-1)}\\\\\\=\dfrac{3x^2+13x-13}{3x(x-1)}[/tex]

        Hence, the answer is:

                3x(x-1)