To investigate the relationship between enzyme activity and substrate concentration, a student is supposed to prepare a reaction solution containing 0.25% substrate. instead, the student prepares a reaction solution containing 0.025% substrate. what effect would this error have on the outcome of the experiment? [2 pt; l2; i.a.5]

as i know for finding the speed of an enzyme to do it's work this formula is used
v=v max *[s]/k m +[s]
km shows the amount of substrate we need to make the enzyme work with half of it's max speed and [s] shows the substrate.
we can say that 0.025/0.25=0.1 so the speed is about 0.1 of we wanted to
investigate at the beginning (we don't consider [s] in the Denominator to solve it easier)

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ogorwyne ogorwyne · Answer 2 · 2021-10-14T13:43:05+02:00

The effect that this error is going to have on the outcome of this experiment is that completion would be slower than expected.

As the substrate concentration gets more increased, the rate of reaction would also rise. When it gets to the point of saturation, it would then become constant.

This question tells us that the student used 0.025% of substrate instead of the 0.25% that he should have used.

With the explanation above, given that 0.025 shows a decrease, it is easy to tell that the rate of completion is going to be slower than what it should be.

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