Respuesta :

atski
Try a double displacement. 
[tex]Pb ^{2+} ClO3^{-} going . to Na{+} , I{-} [/tex]

So double displacement is going to form

PbI2 and NaClO3

Put the products in now w/o balancing yet

Pb(ClO3)2 + NaI --> PbI2 + NaClO3

Balance it now and add phase 
Pb(ClO3)2 (aq)  + 2NaI (ag) --> PbI2 (s)  + 2NaClO3 (aq) 


And that's it

Explanation:

A balanced equation is defined as the equation which contains same number of atoms on both reactant and product side.

For example, [tex]Pb(ClO_{3})_{2}(aq) + NaI(aq) \rightarrow PbI_{2}(s) + NaClO_{3}(aq)[/tex]

So, number of atoms on reactant side are as follows.

  • Pb = 1
  • [tex]ClO_{3})_{2}[/tex] = 2
  • Na = 1
  • I = 1

Number of atoms on product side are as follows.

  • Pb = 1
  • [tex]ClO_{3})_{2}[/tex] = 1
  • Na = 1
  • I = 2

Hence, to balance this chemical equation we multiply NaI with 2 on reactant side and we also multiply [tex]NaClO_{3}[/tex] by 2 on product side.

Therefore, the balanced reaction equation will be as follows.

         [tex]Pb(ClO_{3})_{2}(aq) + 2NaI(aq) \rightarrow PbI_{2}(s) + 2NaClO_{3}(aq)[/tex]

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