Respuesta :

Louli
Answer:
1.7 * 10^-5

Explanation:
1- get the number of moles of PbCl2:
number of moles = mass / molar mass
number of moles = 0.45 / 278.1 = 1.618 * 10^-3 moles

2- get the concentration of Pb2+:
molarity = number of moles of solute / volume of solution in liters
molarity = (1.618 * 10^-3) / (0.1) = 0.0162 M

3- getting concentration of Cl-:
PbCl2(s) <==> Pb2+(aq) + 2Cl-(aq) 
We can note that:
For a certain amount of Pb2+ formed, twice this amount of Cl- is formed.
This means that:
for 0.0162 M of Pb2+, 2*0.0168 = 0.0324 M of Cl- is formed

4- getting Ksp:
Ksp = [Pb2+][Cl-]²
Ksp = (0.0162)*(0.0324)²
Ksp = 1.7 * 10^-5

Hope this helps :)

The value of solubility product constant (Ksp) for PbCl₂, if its solubility is 0.45 g/100 ml of solution is 1.7 × 10⁻⁵.

How do we calculate moles?

Moles of any substance will be calculated by using below formula as:

n = W/M, where

W = given mass

M = molar mass

Given chemical reaction is:

PbCl₂(s) → Pb²⁺(aq) + 2Cl⁻(aq)

Moles of 0.45g of PbCl₂ = 0.45 / 278.1 = 1.618 × 10⁻³ moles

Concentration of PbCl₂ in 100mL or 0.1L will be calculated by using the below formula:

M = n/V

M = (1.618 × 10⁻³) / 0.1 = 0.0162 M

From the stoichiometry of the reaction, it is clear that 1 mole of PbCl₂ will produce 1 mole of Pb²⁺ and 2 moles of Cl⁻.

So, value of Ksp of PbCl₂ will be calculated as:

Ksp = [Pb²⁺][Cl⁻]²

Ksp = (0.0162)(0.0324)²

Ksp = 1.7 × 10⁻⁵

Hence, value of Ksp is 1.7 × 10⁻⁵.

To know more about Ksp, visit the below link:

https://brainly.com/question/7185695

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