C3H8 (propane) undergoes combustion to produce water and carbon (IV) oxide according to equation below
C3H8(g) + 5 O2(g) ----> 3 CO2(g) + 4 H2O(l)
calculate the moles of C3H8 used
mole = mass/molar mass
molar mass of C3H8 = ( 12x3 )+( 1 x 8)=44 g/mol
moles of C3H8= 5g/ 44 g/mol= 0.114 moles
by use of mole ratio between C3H8 to H2O which is 1:4 therefore the mole of water= 0.114 x4=0.456 moles
mass of water =moles of water x molar mass of water
that is 0.456 moles x 18g/mol = 8.208 grams
