Answer:
[tex]114.8\ ft^{2}[/tex]
Step-by-step explanation:
we know that
The area of a trapezoid is equal to
[tex]A=\frac{1}{2}(b1+b2)h[/tex]
In this problem we have
[tex]b1=12\ ft[/tex]
[tex]b2=15\ ft[/tex]
[tex]h=8.5\ ft[/tex] ----> the height of the trapezoid is the perpendicular distance between the bases
substitute the values
[tex]A=\frac{1}{2}(12+15)(8.5)[/tex]
[tex]A=\frac{1}{2}(27)(8.5)=114.75\ ft^{2}[/tex]
Round to the nearest tenth
[tex]114.75=114.8\ ft^{2}[/tex]
