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1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?
- We have the following data:
Vo (initial volume) = 1.00 L
V (final volume) = 473 mL → 0.473 L
Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)
P (final pressure) = ? (in atm)
- We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:
[tex]P_0*V_0 = P*V[/tex]
[tex]1*1 = P*0.473[/tex]
[tex]1 = 0.473\:P[/tex]
[tex]0.473\:P = 1[/tex]
[tex]P = \dfrac{1}{0.473}[/tex]
[tex]\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}[/tex]
Answer:
The new pressure of the gas is 2.11 atm
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[tex]\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}[/tex]
The new pressure of the gas is 2.11 atm.
What is STP?
Standard temperature and pressure, abbreviated STP, refers to nominal conditions in the atmosphere at sea level.
Given data:
[tex]V_0[/tex] (initial volume) = 1.00 L
V (final volume) = 473 mL =0.473 L
[tex]P_0[/tex] (initial pressure) = 1 atm (pressure exerted by the atmosphere in STP)
P (final pressure) = ? (in atm)
We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:
[tex]V_0[/tex] [tex]P_0[/tex] =VP
1.00 L x 1 atm = 0.473 L x P
P = 2.11 atm.
Hence, the new pressure of the gas is 2.11 atm.
Learn more about STP here:
https://brainly.com/question/1626157
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