the sum of three consecutive odd integers is 69.
1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
2x-1 + 2x+1 + 2x+3 = 69
6x + 3 = 69
2x + 1 = 23
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So 2x-1 = 21
And 2x+3 = 25
x be the first odd integer
x + 2 be the 2nd odd integer
x + 4 be the 3rd odd integer
solution:
1st odd integer + 2nd odd integer + 3rd odd integer = 69
x + (x+2) + (x+4)= 69
3x + 6 = 69
3x = 69 - 6
3x = 63 (dividing both sides by three)
x = 21
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x=21
x+2=23
x+4=25
therefore, the 1st integer is 21, the 2nd is 23 and the 3rd is 25...
