Let's use a systems of equations to solve for our answers. Let's consider the amount of 2-point baskets a and the amount of 3-point baskets b.
Regarding the amount of points scored in the game, 80 points compromised some number of 2-point and 3-point baskets. Putting this into an equation, we understand that 80 = 2a + 3b.
Regarding the amount of baskets made in the game, we know that there was a total of 37 baskets made. Putting this into an equation, we get that 37 = a + b
Now, let's set up our system:
2a + 3b = 80
a + b = 37
Now, we can solve this system:
2a + 3b = 80
2a + 2b = 74
b = 6.
Given that 37 = a + b = a + 6, we know that a = 31.
Thus, the team made 31 two-point baskets and 6 three-point baskets.