Respuesta :
The acceleration of the baseball is:
[tex]a= \frac{v_f-v_i}{\Delta t} [/tex]
where [tex]v_f[/tex] and [tex]v_i[/tex] are the final and initial speed of the ball, and [tex]\Delta t[/tex] is the time interval in which the force acted.
Replacing the numbers, we get
[tex]a= \frac{30 m/s-0m/s}{0.5 s}=60 m/s^2 [/tex]
And at this point, we can use Newton's second law F=ma to find the value of the force of the pitching machine:
[tex]F=ma=(0.15 kg)(60 m/s^2)=9 N[/tex]
[tex]a= \frac{v_f-v_i}{\Delta t} [/tex]
where [tex]v_f[/tex] and [tex]v_i[/tex] are the final and initial speed of the ball, and [tex]\Delta t[/tex] is the time interval in which the force acted.
Replacing the numbers, we get
[tex]a= \frac{30 m/s-0m/s}{0.5 s}=60 m/s^2 [/tex]
And at this point, we can use Newton's second law F=ma to find the value of the force of the pitching machine:
[tex]F=ma=(0.15 kg)(60 m/s^2)=9 N[/tex]
Answer:
So F=ma
The acceleration of the baseball is:
where and are the final and initial speed of the ball, and is the time interval in which the force acted.
Replacing the numbers, we get
And at this point, we can use Newton's second law F=ma to find the value of the force of the pitching machine: