The pressure of the gas above the water when the solubility of the gas is 1.0 g/L is 0.75 atm
Henry's law
This states that the solubility of a gas in liquids at constant temperature is proportional to its pressure. Mathematically, it can be expressed as
S₁ / P₁ = S₂ / P₂
Where
- S₁ is the initial solubility
- P₁ is the initial pressure
- S₂ is the new solubility
- P₂ is the new pressure
How to determine the new pressure
From the question given above, the following data were obtained
- Initial solubility (S₁) = 4 g/L
- Initial pressure (P₁) = 3 atm
- New solubility (S₂) = 1 g/L
- New pressure (P₂) = ?
S₁ / P₁ = S₂ / P₂
4 / 3 = 1 / P₂
Cross multiply
4 × P₂ = 1 × 3
4 × P₂ = 3
Divide both side by 4
P₂ = 3 / 4
P₂ = 0.75 atm
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