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Determine the molecular formula of a compound that is 54.5% C, 13.7% H, and 31.8% N. The molar mass is 88.0.

Respuesta :

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C : H : N

54.5/12 : 13.7/1 : 31.8/14

4.5/2.3 : 13.7/2.3 : 2.3/2.3

2 : 6 : 1

this is the ratio for emperical fromula
C2H6N
now the emperical formula mass will be
12x2 + 1x6 + 14x1
=44

the value to multiple the emperical formula =
molar mass/emperical formula mass
88/44= 2

2( C2H6N)

= C4H12N2

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