Respuesta :
The net ionic equation for the neutralization reaction involving equal molar amount amount of HNo3 and KoH is
H^+ + OH^- = H2O (l)
explanation
write the chemical equation
HNO3 (aq) + KOH(aq) = KNO3(aq) +H2O (l)
ionic eequation
H^+(aq) + NO3^- (aq) + K^+9aq) OH^-(aq) = K^+ (aq) + NO3^-(aq) + H2O(l)
cancel the spectator ions( ions which does not take place in equation ) for this case is NO3^- and No3^-
thus the net ionic is
H^+(aq) + OH^- (aq) = H2O(l)
H^+ + OH^- = H2O (l)
explanation
write the chemical equation
HNO3 (aq) + KOH(aq) = KNO3(aq) +H2O (l)
ionic eequation
H^+(aq) + NO3^- (aq) + K^+9aq) OH^-(aq) = K^+ (aq) + NO3^-(aq) + H2O(l)
cancel the spectator ions( ions which does not take place in equation ) for this case is NO3^- and No3^-
thus the net ionic is
H^+(aq) + OH^- (aq) = H2O(l)
Answer: H⁺(aq) + OH⁻(aq) --> H₂O(l)
Explanation:
1) Write the molecular chemical equation:
HNO₃(aq) + KOH(aq) ---> H₂O(l) + KNO₃(aq)
2) Identify the kind of reaction:
It is a acid base neutralization, which is a double replacement equation.
3) Set the ionization (dissociation) of the acid and the base compounds:
i) HNO₃(aq) ---> H⁺ (aq) + NO₃⁻ (aq)
ii) KOH (aq) --> K⁺ (aq) + OH⁻ (aq)
4) Identify whether the products are soluble ionic compounds and they dissociate in water or remain solids (phases).
i) KNO₃ is soluble, so it will dissociate: KNO₃(aq) --> K⁺(aq) + NO₃⁻(aq)
ii) H₂O slightly dissociates, so it will remain liquid: H2O (l)
5) Write the total ionic equation:
H⁺ (aq) + NO₃⁻(aq) + K⁺(aq) + OH⁻ (aq) --> K⁺ (aq) + NO₃⁻(aq) + H₂O(l)
6) Eliminate the spectator ions (those that are repeated in reactant and product sides, K⁺(aq) y NO₃⁻(aq):
H⁺(aq) + OH⁻(aq) --> H₂O(l)
That is the net ionic equation.
Explanation:
1) Write the molecular chemical equation:
HNO₃(aq) + KOH(aq) ---> H₂O(l) + KNO₃(aq)
2) Identify the kind of reaction:
It is a acid base neutralization, which is a double replacement equation.
3) Set the ionization (dissociation) of the acid and the base compounds:
i) HNO₃(aq) ---> H⁺ (aq) + NO₃⁻ (aq)
ii) KOH (aq) --> K⁺ (aq) + OH⁻ (aq)
4) Identify whether the products are soluble ionic compounds and they dissociate in water or remain solids (phases).
i) KNO₃ is soluble, so it will dissociate: KNO₃(aq) --> K⁺(aq) + NO₃⁻(aq)
ii) H₂O slightly dissociates, so it will remain liquid: H2O (l)
5) Write the total ionic equation:
H⁺ (aq) + NO₃⁻(aq) + K⁺(aq) + OH⁻ (aq) --> K⁺ (aq) + NO₃⁻(aq) + H₂O(l)
6) Eliminate the spectator ions (those that are repeated in reactant and product sides, K⁺(aq) y NO₃⁻(aq):
H⁺(aq) + OH⁻(aq) --> H₂O(l)
That is the net ionic equation.