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The area of the ice surface of a skating rink is about 221 yd2. The rink is about the shape of a rectangle where the ice-surface width is 4 yd longer than its length. Find the dimensions of the surface

Respuesta :

calculista
Let
x----------> length of rectangle  surface
y---------->width of rectangle surface

we know that
x*y=221------------> equation 1
and
y=x+4--------------> equation 2

I substitute 2 in 1
x*[x+4]=221--------> x²+4x-221=0

using a graph tool---------> to calculate the quadratic equation

see the attached figure
the solution is
x=13
y=x+4-------> y=13+7-----> y=17

the answer is 
the length of rectangle surface is 13 yd
the width of rectangle surface is 17 yd

Ver imagen calculista

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