Respuesta :
From the balanced equation o the reaction:
2Mg + O2 → 2MgO
from this equation we can see that:
1 mole of O2 gives → 2 moles of MgO
So 0.2 moles of O2 will give → ????
So the number of moles of MgO = (0.2 mol O2 )* (2 mol MgO) / (1 mol of O2)
= 0.4
2Mg + O2 → 2MgO
from this equation we can see that:
1 mole of O2 gives → 2 moles of MgO
So 0.2 moles of O2 will give → ????
So the number of moles of MgO = (0.2 mol O2 )* (2 mol MgO) / (1 mol of O2)
= 0.4
The reaction of 0.20 moles of oxygen on complete utilization produces 0.40 moles of MgO.
From the reaction,
1 mole of oxygen produced 2 moles of MgO.
So, 0.20 moles of oxygen produces:
Moles of MgO produced = 0.20 [tex]\times[/tex] 2
Moles of MgO produced = 0.40 moles.
The reaction of 0.20 moles of oxygen on complete utilization produces 0.40 moles of MgO.
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