Answer:
18 inches
Step-by-step explanation:
We have that,
Length of the photo, [tex]L_{s}[/tex] = 6 inches and Width of the photo, [tex]W_{s}[/tex] = 4 inches.
Now, the photo is enlarged with the new width i.e. [tex]W_{l}[/tex] is 12 inches.
Let, the length of the enlarged photo i.e. [tex]L_{l}[/tex] be x inches.
Since, the ratio between length and width remains same, we have the relation,
[tex]\frac{L_{s}}{W_{s}}=\frac{L_{l}}{W_{l}}[/tex]
i.e. [tex]\frac{6}{4}=\frac{x}{12}[/tex]
i.e. [tex]\frac{3}{2}=\frac{x}{12}[/tex]
i.e. [tex]x=\frac{3\times 12}{2}[/tex]
i.e. [tex]x=\frac{36}{2}[/tex]
i.e. [tex]x=18[/tex]
Hence, the length of enlarged photo is 18 inches.
