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A chemist dilutes a 1.0 mL sample of 2.0 M KNO3 by adding water to it. If the concentration of the solution that is obtained is 0.0080 M, what is its volume?
Use: Mi Vi = Mf Vf

A.) 125 mL
B.) 250 mL
C.) 500 mL
D.) 2,000 mL

Respuesta :

Willchemistry
Mi = 2.0 M

Vi = 1.0 mL

Mf = 0.0080 M

Vf = ?

Mi * Vi = Mf* Vf

2.0 * 1.0 = 0.0080 * Vf

2 = 0.0080* Vf

Vf = 2 / 0.0080

Vf = 250 mL

answer b

hope this helps!.

Answer: Option (B) is the correct answer.

Explanation:

The given data is as follows.

              [tex]M_{1}[/tex] = 2.0 M,           [tex]V_{1}[/tex] = 1.0 ml

              [tex]M_{2}[/tex] = 0.008 M,         [tex]V_{2}[/tex] = ?

Therefore, calculate the volume of given solution as follows.

              [tex]M_{1} \times V_{1}[/tex] = [tex]M_{2} \times V_{2}[/tex]

Now, putting the given values into the above formula as follows.

            [tex]M_{1} \times V_{1}[/tex] = [tex]M_{2} \times V_{2}[/tex]

            [tex]2.0 M \times 1.0 ml[/tex] = [tex]0.008 M \times V_{2}[/tex]    

                   [tex]V_{1}[/tex] = 250 ml

Therefore, volume of the solution obtained is 250 ml.

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