Respuesta :
The first thing that we want to do is factor the quadratic expression in the numerator.
4x2 - 15x + 9
(4x - 3)(x - 3)
Now, we have the following equation:
[tex] \frac{(4x-3)(x-3)}{(x-3)} [/tex]
Now, both numerator and denominator have an (x-3), so you can divide (x-3) from the numerator
[tex] \frac{(4x-3)(x-3)}{(x-3)} [/tex]
[tex] \frac{(4x-3)(1)}{(1)} [/tex]
So, we are left with 4x-3
Hope this helped!! :D
4x2 - 15x + 9
(4x - 3)(x - 3)
Now, we have the following equation:
[tex] \frac{(4x-3)(x-3)}{(x-3)} [/tex]
Now, both numerator and denominator have an (x-3), so you can divide (x-3) from the numerator
[tex] \frac{(4x-3)(x-3)}{(x-3)} [/tex]
[tex] \frac{(4x-3)(1)}{(1)} [/tex]
So, we are left with 4x-3
Hope this helped!! :D
Answer:
Larry thinks that the quotient of
4x2 + 7x − 15
x + 3
is 4x − 5. Complete the explanation of how you can check his answer using multiplication. Then, check his answer. Is Larry correct?
You can check the quotient by multiplying the quotient by the , or . The product is , so Larry correct.
Step-by-step explanation:
yes help me