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A line has a slope of -2/3 and passes through the point (–3, 8). What is the equation of the line?

y=2/3x + 6

y=2/3x + 8

y=6x-2/3


y=8x-2/3

Respuesta :

 Note that an equation in the slope intercept form is y= mx + b where the slope is m and the y-intercept is b. Since we already know the slope ([tex] \frac{2}{3} [/tex], we can insert that for m.) [tex]y = \frac{2}{3} + b[/tex] and this cancels out answer choice y = 6x - 2/3 and 8x - 2/3
Ver imagen MissSmartiez

The equation of the line is y = (-2/3)x + 6 if the line has a slope of -2/3 and passes through the point (–3, 8) option (A) is correct.

What is a straight line?

A straight line is a combination of endless points joined on both sides of the point.

The correct options are:

y=-2/3x + 6

y=2/3x + 8

y=6x-2/3

y=8x-2/3

We have:

A line has a slope of -2/3 and passes through the point (–3, 8).

As we know, the slope-point form of a line is:

(y - y1) = m(x - x1)

m = -2/3

x1 = -3

y1 = 8

Plug the above values in the equation:

(y - 8) = (-2/3)(x - (-3))

(y - 8) = (-2/3)(x + 3)

3(y - 8) = -2(x + 3)

3y - 24 = -2x - 6

3y = -2x - 6+24

3y = -2x + 18

y = (-2/3)x + 6

Thus, the equation of the line is y = (-2/3)x + 6 if the line has a slope of -2/3 and passes through the point (–3, 8) option (A) is correct.

Learn more about the straight line here:

brainly.com/question/3493733

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