First, we need to figure out the probability of landing on white one time. The probability of landing on black is 1/2, and the probability of landing on red is 1/3. If we add these probabilities together we get:
[tex] \frac{1}{2}+ \frac{1}{3} = \frac{3}{6}+ \frac{2}{6} = \frac{5}{6} [/tex]
So if there is a 5/6 chance of NOT landing on white, then there must be a 1/6 chance of landing on white.
To find the probability of landing on white 4 times, multiply 1/6 to itself 4 times.
[tex]( \frac{1}{6})^4 = \frac{1}{1296} [/tex]
The answer is D.
