Identify the factor terms by grouping: 5x3 – 4x2 + 20x – 16

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16-02-2018
Mathematics

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Identify the factor terms by grouping: 5x3 – 4x2 + 20x – 16

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mashpatatos mashpatatos · Answer 1 · 2018-02-16T16:27:16+01:00

5x3-4x2-20x+16=0 Three solutions were found : x = 4/5 = 0.800 x = 2 x = -2Reformatting the input :Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).
Step by step solution :Step 1 :Equation at the end of step 1 : (((5 • (x3)) - 22x2) - 20x) + 16 = 0 Step 2 :Equation at the end of step 2 : ((5x3 - 22x2) - 20x) + 16 = 0 Step 3 :Checking for a perfect cube : 3.1 5x3-4x2-20x+16 is not a perfect cube
Trying to factor by pulling out : 3.2 Factoring: 5x3-4x2-20x+16
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 5x3+16 Group 2: -4x2-20x
Pull out from each group separately :
Group 1: (5x3+16) • (1)Group 2: (x+5) • (-4x)

I hope it helps

erinna erinna · Answer 2 · 2019-10-22T07:51:18+02:00

Answer:

[tex](5x-4)(x^2+4)[/tex]

Step-by-step explanation:

Consider the given expression

[tex]5x^3-4x^2+20x-16[/tex]

We need to find the factor form of given expression.

Using grouping method we get

[tex](5x^3-4x^2)+(20x-16)[/tex]

Taking out highest common factors from each group.

[tex]x^2(5x-4)+4(5x-4)[/tex]

Taking out common factors.

[tex](5x-4)(x^2+4)[/tex]

Therefore, the factored form of given expression is [tex](5x-4)(x^2+4)[/tex].