Answer:
sin(x)cos(x) = -4/9
Step-by-step explanation:
Square the given equation, and solve for the desired product.
(sin(x) +cos(x))^2 = (1/3)^2
sin(x)^2 +2sin(x)cos(x) +cos(x)^2 = 1/9
1 + 2sin(x)cos(x) = 1/9 . . . use the trig identity for sin²+cos²
2sin(x)cos(x) = -8/9 . . . . . subtract 1
sin(x)cos(x) = -4/9 . . . . . . divide by 2
