First, let's convert the given line equation into slope-intercept form to find the slope.
Let's start converting by subtracting both sides by 3x.
[tex]-2y-5=-3x[/tex]
Add both sides by 5.
[tex]-2y=-3x+5[/tex]
Divide both sides by -2.
[tex]y= \frac{3}{2} x- \frac{5}{2} [/tex]
The slope of the equation given is 3/2. Since the point-slope form line is parallel to that, the point-slope form equation must also have a slope of 3/2.
Now, let's use point-slope form.
For a line with slope m and that passes through [tex](x_1,y_1)[/tex], the point slope form equation is the following:
[tex]y-y_1=m(x-x_1)[/tex]
We know the passing point and the slope. Now, let's plug them into the point-slope form formula.
[tex]y-8= \frac{3}{2} (x-(-8))[/tex]
[tex]y-8= \frac{3}{2} (x+8)[/tex]
That is your answer for the point-slope form equation.
To change this to general form, distribute first.
[tex]y-8= \frac{3}{2} x+12[/tex]
Subtract both sides by [tex]\frac{3}{2} x[/tex] and 12.
[tex]- \frac{3}{2} x+y-20=0[/tex]
Multiply both sides by -2
[tex]3x-2y+40=0[/tex]
That's your answer for the general form equation.
I hope this helps and have an awesome day! :)