Respuesta :

carlafossil320
From the information given, we can see that the mass of Iodine-131 halves about every 8 days. There are 3 sets of 8 days in 24 days, so we will need to halve the mass of the sample 3 times:
50÷2=25
25÷2=12.5
12.5÷2=6.25
So after 24 days, the Iodine-131 sample will be 6.25g.
Here's a formula to figure this out, when dealing with bigger numbers:
[tex]a = i \times ({ \frac{1}{2} })^{ \frac{t}{h} } [/tex]
Where
a = final amount
i = initial amount
1/2 is used because we are dealing with half lifes
t = time
h = half life of the isotope
raphealnwobi

6.25 g of Iodine-131 is left after 24 days

The half life of a subtance is given by:

[tex]N=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\Where\ N\ is\ the\ substance\ remaining\ after\ period\ t, N_o\ is\ the\ \\amount\ of\ original\ substance\ and \ t_\frac{1}{2} \ is\ half\ life.\\\\Given \ that:\\\\t_\frac{1}{2} =8\ days,t=24\ days,N_o=50\ g, hence:\\\\N=50(\frac{1}{2} )^\frac{24}{8} =6.25\ g[/tex]

6.25 g of Iodine-131 is left after 24 days

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