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in a laboratory, under favorable conditions, a bacteria grows at an exponential rate. the number of cells C in the population is modeled by the function C(t)=ab^t, where a and b are constants and t is measured in hours.

T                C(t)

---            -------
0                 8
-----           --------
1                 24

Which function can be used to find the number of cells of bacteria in the population at time t?


A. C(t)=8(1)^t

B. C(t)=24(1)^t

C. C(t)=8(3)^t

D. C(t)=24(3)^t

Respuesta :

sqdancefan
Selection C is appropriate.

_____
A. The population is constant at 8.

B. The population is constant at 24.

C. Matches the problem description.

D. The initial population is 24 and after 1 hour is 72.
SociometricStar

Answer:

Eponential model is given by [tex]C(t)=8(3)^t[/tex]

C is the correct option.

Step-by-step explanation:

From the given table, we have

For t = 0, C = 8

For t = 1, C = 24

The given model is [tex]C(t)=ab^t[/tex]

Plugging, t = 0, C = 8 in the equation, we get

[tex]8=ab^0\\8=a\cdot1\\a=8[/tex]

Now, plugging t = 1, C = 24 and a = 8 in the given exponential model

[tex]24=8b^1\\24=8b\\b=3[/tex]

Therefore, the exponential model is given by

[tex]C(t)=8(3)^t[/tex]

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