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An incident ray strikes a boundary at a 72.5-degree angle, resulting in an angle of refraction of 39.6 degrees. The index of refraction of the first medium is 1.0003.

What is medium 1?


What is medium 2?

An incident ray strikes a boundary at a 725degree angle resulting in an angle of refraction of 396 degrees The index of refraction of the first medium is 10003 class=

Respuesta :

Medium 1: Air
Medium 2: Lucite

Answer:

medium 1 = air

medium 2 = Lucite

Explanation:

Part a)

here the refractive index of first medium is 1.0003

so from the given table this is the refractive index of air

so medium 1 is AIR

Part b)

As per law of refraction we know that

[tex]n_1sin\theta_1 = n_2 sin\theta_2[/tex]

here we know that

[tex]n_1 = 1.0003[/tex]

[tex]\theta_1 = 72.5 [/tex]

[tex]\theta_2 = 39.6 [/tex]

now from Snell's law we will have

[tex]1.0003 sin(72.5) = n_2 sin39.6[/tex]

so we have

[tex]n_2 = \frac{1.0003(sin72.5)}{sin39.6}[/tex]

so we have

[tex]n_2 = 1.50[/tex]

so medium 2 is LUCITE

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