A prism has total surface area of 360 m2 and volume of 60 m3.

If the length, width, and height are reduced to half their original sizes, what will be the following?
A. the new surface area
B. the new volume

Solve for the following if the height is tripled.
C. the new volume

Respuesta :

1.
a. 180m²b. 7.5m³
2.a.1620m²b. 180m³

Answer:

The answers are:

A. 7.5 m³

B. 90 m²

C. 180 m³

Step-by-step explanation:

Let us answer the questions about the volume. We know that the volume of a prism is V=l*w*h, where l stands for the length, w stands for the width and h stands for the height.

Volumes.

A prism with half the original sizes. From the original prism we know that V=l*w*h=60 m³. The new prism have dimension l'=l/2, h'=h/2 and w'=w/2. Then, its volume V' is

V' = l'*h'*w' = (l/2)*(h/2)*(w/2) = (l*w*h)/8=V/8 = 60/8 = 7.5 m³.

A prism with height tripled. In this case all the dimension are the same, except for the height: this l'=l, w'=w and h'=3*h. Then, the new volume V' is

V' = l'*h'*w' = l*(3*h)*w = 3*l*h*w=3*V = 3*60 = 180 m³.

Surface area.

A prism with half the original sizes.

The formula for the surface area of a prism is

[tex]A = 2A_b + P_bh[/tex]

where [tex]A_b[/tex] stands for the area of the base and [tex]P_b[/tex] stands for the perimeter of the base. As the base is rectangle,  [tex]A_b=lw[/tex] and [tex]P_b = 2(l+w)[/tex].

Hence,

[tex]A = 2lw + 2(l+w)h.[/tex]

Then, the area of the new prism is A' ()recall that the dimension of the new prism are l'=l/2, h'=h/2 and w'=w/2).

[tex]A' = 2(l')(w') + 2(l'+w')h' = 2\frac{l}{2}\frac{w}{2} + 2(\frac{l}{2}+\frac{w}{2})\frac{h}{2} = \frac{2lw}{4} + 2\frac{l+w}{2}\frac{h}{2} = \frac{2lw}{4} + \frac{2(l+w)h}{4}.[/tex]

In this expression we can extract a common factor 1/4, thus

[tex]A' = \frac{1}{4}(2lw + 2(l+w)h) = \frac{1}{4}A = 360/4 = 90 m^2[/tex]