Answer:
41.2 feet
Step-by-step explanation:
Refer the attached figure .
A scuba diver has a taut rope connecting the dive boat to an anchor on the ocean floor. The rope is 90 feet i.e. AC = 90 feet.
The depth of water i.e. AB = 80 feet.
We are supposed to find how far is the anchor from a point directly below the boat i.e. BC
So, to find BC we will use Pythagoras theorem :
[tex]Perpendicular^2+Base^2=Hypotenuse^2[/tex]
[tex]AB^2+BC^2=AC^2[/tex]
[tex]80^2+BC^2=90^2[/tex]
[tex]6400+BC^2=8100[/tex]
[tex]BC^2=8100-6400[/tex]
[tex]BC^2=1700[/tex]
[tex]BC=\sqrt{1700}[/tex]
[tex]BC=41.2 feet[/tex]
Thus the anchor is 41.2 feet from a point directly below the boat.
