A 0.580-kg rock is tied to the end of a string and is swung in a circle with a radius of 0.500 meters. The velocity of the rock is 4.50 m/s. What is the centripetal force acting on the rock

Respuesta :

[tex]F = m \frac{v^2}{r} [/tex]

[tex]F= 0.58 \frac{4.5^2}{0.5} = 23.49 N [/tex]

Answer:

 23.5 Newtons

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