when the first reaction equation is:
N2(g) + O2(g) → 2NO(g)
when Keq = the concentrations of the products / concentrations of the reactants
so, Keq1 = [NO]^2 / [N2][O2]
∴ 4.2 x 10^-31 = [NO]^2/[N2][O2] .
and when we multiply this reaction coefficient by 2 so the equilibrium reaction equation is:
4 NO(g)→ 2N2(g) + 2O2(g)
this is the reverse reaction equation of the first reaction multiply by 2. so,
Keq2 = [O2]^2[N]^2/[NO]^4 and
Keq2= 1 / (Keq1)^2.
∴Keq2 = 1/ (4.2 X10^-31)^2
= 5,67·10⁶⁰
so, the value of Keq for the reaction below is 5.67 X 10^60
