Respuesta :
Radius of the rings = 10 / 2 = 5 cm 0.05m
Distance between them D = 15 cm = 0.15 m
The charge of left ring is Ql = -20 x 10^-9 C
The charge of right ring is Qr = 20 x 10^-9 C
Since it the electric field at the midpoint, it is same for both rings and the there are opposite charges the electric filed will be sum of electric field of both charges.
Electric field on the left El = (k x Ql) / (D/2)^2 = (4 x k x Ql) / D^2
Electric field on the Right Er = (k x Qr) / (D/2)^2 = (4 x k x Qr) / D^2
Electric field E = El + Er = ((4 x k x Ql) / D^2) + ((4 x k x Qr) / D^2)
E = 4k/ D^2 (Ql + Qr); k is Coulombs constant = 8.99 x 10^9 Nm2Câ’2
E = 4 x 8.99 x 10^9/ 0.15^2 (2n + 2n) = 1598 x 10^9 x 4 x 10^-9 = 6393 N/c
Force f = E x q, q being the charge at the mid point
Force = q x 6393 N/c = 6.393q x 10^3 N
Distance between them D = 15 cm = 0.15 m
The charge of left ring is Ql = -20 x 10^-9 C
The charge of right ring is Qr = 20 x 10^-9 C
Since it the electric field at the midpoint, it is same for both rings and the there are opposite charges the electric filed will be sum of electric field of both charges.
Electric field on the left El = (k x Ql) / (D/2)^2 = (4 x k x Ql) / D^2
Electric field on the Right Er = (k x Qr) / (D/2)^2 = (4 x k x Qr) / D^2
Electric field E = El + Er = ((4 x k x Ql) / D^2) + ((4 x k x Qr) / D^2)
E = 4k/ D^2 (Ql + Qr); k is Coulombs constant = 8.99 x 10^9 Nm2Câ’2
E = 4 x 8.99 x 10^9/ 0.15^2 (2n + 2n) = 1598 x 10^9 x 4 x 10^-9 = 6393 N/c
Force f = E x q, q being the charge at the mid point
Force = q x 6393 N/c = 6.393q x 10^3 N
Each element is made up of three different substances that is electron, proton, and neutron. These electrons revolve around the nucleus.
Since it is the electric field at the midpoint, it is the same for both rings and there are opposite charges the electric field will be the sum of electric field of both charges.
Electric field on the left El = [tex]\frac{k x Ql} {D/2}^2 = \frac{(4*k*Ql)}{ D}^2[/tex]
Electric field on the Right Er =[tex]\frac{(k * Qr)}{(D/2)}^2 = \frac{4 * k * Qr}{ D^2}[/tex]
Electric field [tex]E = El + Er = \frac{4 * k *Ql}{D^2} + \frac{(4 * k * Qr)}{D^2}[/tex]
[tex]E = \frac{4k}{D^2} (Ql + Qr);[/tex]
K is Coulombs constant = [tex]8.99 * 10^9[/tex]
E = [tex]\frac{4 * 8.99 * 10^9}{0.15^2 (2n + 2n)} \\\\= 1598 * 10^9 * 4 * 10^{-9}\\\\ = 6393 N/c[/tex]
Force f = [tex]q * 6393 N/c = 6.393q * 10^3 N[/tex]
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