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Cell membranes contain channels that allow ions to cross the phospholipid bilayer. suppose that a particular potassium channel carries a current of 2.0 pa. how many potassium ions (k ) pass through it in 1.0 ms

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onyebuchinnaji

The number of ions of potassium that pass through is 2.07 x 10⁻²⁰ ions.

The given parameters;

  • current carried by the potassium, I = 2.0 pA
  • time of flow of the current = t = 1 ms

The quantity of charge passed through the ion is calculated as;

Q = It

Q = (2.0 x 10⁻¹²)(1 x 10⁻³)

Q = 2 x 10⁻¹⁵ C

The number of ions that pass through is calculated as;

1 ion = 1 F

1 F = 96500 C

96500 C --------- 1 F

2 x 10⁻¹⁵ C -------- ?

[tex]= \frac{2\times 10^{-15}}{96500} \\\\= 2.07 \times 10^{-20} \ ions[/tex]

Thus, the number of ions of potassium that pass through is 2.07 x 10⁻²⁰ ions.

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