Respuesta :
The length of the side AB of the triangle ABC with angles of 40 and 70 degrees and side BC of 8.5 units is 12.4 units.
How to find the side of a triangle?
The side of the triangle can be found using sine law,
Therefore,
AB / sin 70° = 8.5 / sin 40°
cross multiply
AB sin 40° = 8.5 sin 70°
divide both sides by sin 40°
AB = 8.5 × sin 70 / sin 40°
AB = 8.5 × 0.93969262078 / 0.64278760968
AB = 7.98738727668 / 0.64278760968
AB = 12.4299065421
AB = 12.4 units
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