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What are the solutions of the equation (x – 3)^2 + 2(x – 3) – 8 = 0? Use u substitution to solve.
x = –5 and x = 1
x = –1 and x = 5
x = –1 and x = –7
x = 1 and x = 7

Respuesta :

Unknownly
The solution is x=-1 and x=5. Why? Well like the question states you just have to substitute each number for x. 

((-1)-3)^2+2((-1)-3)-8=0 
16+(-8)-8=0
0=0

((5)-3)^2+2((-1)-3)-8=0
4+4-8=0
0=0 

Each one is true. Hope this helped! :)
abidemiokin

The value of x from the given expression is 1 and -5: Option A is correct.

Given the quadratic expression

[tex](x - 3)^2 + 2(x - 3) - 8 = 0[/tex]

Expand the expression

[tex](x - 3)^2 + 2(x - 3) - 8 = 0\\x^2-6x+9+2x-6-8=0\\x^2-6x+2x+9-6-8=0\\x^2-4x-5=0[/tex]

Factorize the result

[tex]x^2-4x-5=0\\x^2+5x-x-5=0\\x(x+5)-1(x+5) =0\\x-1=0 \ and \ x+5 =0\\x=1 \ and \ x = -5\\[/tex]

Hence the value of x is 1 and -5

Learn more here: https://brainly.com/question/11909547

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