Suppose the population of a small town is 567 in 2011. The population decreases at a rate of 1.5% every year. What will be the population of the town in 2020? Round your answer to the nearest whole number.

Respuesta :

Using an exponential function, it is found that the population of the town in 2020 will be of 495.

What is an exponential function?

A decaying exponential function is modeled by:

[tex]A(t) = A(0)(1 - r)^t[/tex]

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

In this problem:

  • The population of a small town is 567 in 2011, hence [tex]A(0) = 567[/tex].
  • The population decreases at a rate of 1.5% every year, hence [tex]r = 0.015[/tex].

Then:

[tex]A(t) = A(0)(1 - r)^t[/tex]

[tex]A(t) = 567(1 - 0.015)^t[/tex]

[tex]A(t) = 567(0.985)^t[/tex]

2020 is 9 years after 2011, hence:

[tex]A(9) = 567(0.985)^9 = 495[/tex]

The population of the town in 2020 will be of 495.

You can learn more about exponential functions at https://brainly.com/question/25537936

Answer:

495

Step-by-step explanation: