we know that
the volume of the oblique pyramid with a square base is equal to
[tex]V=\frac{1}{3}Bh[/tex]
where
B is the area of the base
h is the height of the pyramid
In this problem
The area of the base is
[tex]B=EF^{2}\ units^{2}[/tex]
[tex]h=AB\ units[/tex]
The two formulas to calculate h are
Applying the Pythagoras Theorem
[tex]h^{2}=AC^{2}-CB^{2}[/tex] ------> [tex]h=\sqrt{AC^{2}-CB^{2}}[/tex]
[tex]h^{2}=AD^{2}-DB^{2}[/tex] ------> [tex]h=\sqrt{AD^{2}-DB^{2}}[/tex]
therefore
the answer is
AB and EF
AC, CB and EF
AD, DB and EF
