Lorne subtracted 6x3 – 2x + 3 from –3x3 + 5x2 + 4x – 7. Use the drop-down menus to identify the steps Lorne used to find the difference.
1. (–3x3 + 5x2 + 4x – 7) + (–6x3 + 2x – 3)
2. (–3x3) + 5x2 + 4x + (–7) + (–6x3) + 2x + (–3)
3. [(–3x3) + (–6x3)] + [4x + 2x] + [(–7) + (–3)] + [5x2]
4. –9x3 + 6x + (–10) + 5x2
5. –9x3 + 5x2 + 6x – 10

Respuesta :

Answer:

The answer on Edg is

1. wrote as addition of the additive inverse

2. wrote terms as addition of opposite

3. grouped like terms

4. combined like terms

After subtraction, we get [tex]-3x^{3}+5x^{2} +6x-10[/tex]

Algebraic subtraction :

We have to subtract [tex]6x^{3} -2x+3[/tex]  from  [tex]3x^{3}+5x^{2} +4x-7[/tex]

As we know that subtraction always happen from same degree of variable.

               [tex]=3x^{3}+5x^{2} +4x-7-(6x^{3}-2x+3 )\\\\=3x^{3}+5x^{2} +4x-7-6x^{3}+2x-3 \\\\=3x^{3}-6x^{3}+5x^{2} +4x+2x-7-3\\ \\ =-3x^{3}+5x^{2} +6x-10[/tex]    

Learn more about the algebraic expression here:

https://brainly.com/question/4344214