Tamara is creating a model of a rectangle. She has 26 inches of yellow ribbon to use for the border of the rectangle. She wants the length, l, to be 3 inches greater than the width, w. Which system of equations could Tamara use to find the dimensions of a rectangle that uses all of the ribbon?






Tamara is creating a model of a rectangle. She has 26 inches of yellow ribbon to use for the border of the rectangle. She wants the length, l, to be 3 inches greater than the width, w. Which system of equations could Tamara use to find the dimensions of a rectangle that uses all of the ribbon?












Respuesta :

P = 2(L + W)
L = W + 3
these would be ur equations...and u would sub in 26 for P

Answer:

[tex]26=2L+2W[/tex]

[tex]L=W+3[/tex]

Step-by-step explanation:

Let,

L be the length of the rectangle

W be the width of the rectangle

As Tamara will use the ribbon for the border of rectangle, this means we need the perimeter of rectangle.

Perimeter is given as :

[tex]P=2L+2W[/tex]

As Tamara is using 26 inches of ribbon so perimeter is 26.

Equation becomes,

[tex]26=2L+2W[/tex]  ..........(1)

Tamara wants the length to be 3 inches greater than the width, so equation becomes:

[tex]L=W+3[/tex]   ..........(2)

Substituting equation 2 in equation 1:

[tex]26=2(W+3)+2W[/tex]

=>[tex]26=2W+6+2W[/tex]

=>[tex]4W=26-6[/tex]

[tex]W=5[/tex] inches.

And,

[tex]L=W+3[/tex]

= [tex]5+3=8[/tex] inches

Therefore, we can say that the system of equations used are :

[tex]26=2L+2W[/tex]

[tex]L=W+3[/tex]